本文共 2103 字，大约阅读时间需要 7 分钟。

1031 Hello World for U （20 分)

常规代码

#include 
   
    #include 
    
     using namespace std;int main() {   	string S;	cin >> S;	int Len = S.size();	int VLen = (Len + 1) / 3;	char U[40][40];	for (int i = 0; i < 40; i++)		for (int j = 0; j < 40; j++) U[i][j] = ' ';	int i = 0;	if ((Len + 1) % 3 == 0) {   		for (int row = 0; row < VLen; row++) {   			if (row == VLen - 1) {   				for (int k = 0; k <= VLen; k++)					U[row][k] = S[i++];			}			else U[row][0] = S[i++];		}		for (int row = VLen - 2; row >= 0; row--)			U[row][VLen] = S[i++];		int p, q;		for (p = 0; p < VLen; p++) {   			for (q = 0; q <= VLen; q++) {   				if (q == VLen) cout << U[p][q] << endl;				else cout << U[p][q];			}		}	}	else if ((Len + 1) % 3 == 1) {   		for (int row = 0; row < VLen; row++) {   			if (row == VLen - 1)				for (int k = 0; k <= VLen + 1; k++) U[row][k] = S[i++];			else U[row][0] = S[i++];		}		for (int row = VLen - 2; row >= 0; row--) U[row][VLen + 1] = S[i++];		int p, q;		for (p = 0; p < VLen; p++) {   			for (q = 0; q <= VLen + 1; q++) {   				if (q == VLen + 1) cout << U[p][q] << endl;				else cout << U[p][q];			}		}	}	else if ((Len + 1) % 3 == 2) {   		for (int row = 0; row <= VLen; row++) {   			if (row == VLen) for (int k = 0; k <= VLen; k++) U[row][k] = S[i++];			else U[row][0] = S[i++];		}		for (int row = VLen - 1; row >= 0; row--) U[row][VLen] = S[i++];		int p, q;		for (p = 0; p <= VLen; p++) {   			for (q = 0; q <= VLen; q++) {   				if (q == VLen) cout << U[p][q] << endl;				else cout << U[p][q];			}		}	}	return 0;}
    
   

优化代码

#include
   
    #include
    
     #include
     
      using namespace std;int main() {   	char S[100];	scanf("%s", S);	int Len = strlen(S);	int n1 = (Len + 2) / 3, n3 = n1, n2 = Len + 2 - n1 * 2;	char U[40][40];	for (int i = 1; i <= n1; i++)		for (int j = 1; j <= n2; j++) U[i][j] = ' ';	int pos = 0;	for (int i = 1; i <= n1; i++) U[i][1] = S[pos++];	for (int j = 2; j <= n2; j++) U[n1][j] = S[pos++];	for (int k = n3 - 1; k > 0; k--) U[k][n2] = S[pos++];	for (int i = 1; i <= n1; i++) {   		for (int j = 1; j <= n2; j++) cout << U[i][j];		cout << endl;	}	return 0;}
     
    
   

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